Linear Algebra Examples

\log (x + 9) = 1 - \log (x)

$\log (x + 9) = 1 - \log (x)$

Step 1

Set the argument in

\log (x + 9)

$\log (x + 9)$ greater than

0

$0$ to find where the expression is defined.

x + 9 > 0

$x + 9 > 0$

Step 2

Subtract

9

$9$ from both sides of the inequality.

x > - 9

$x > - 9$

Step 3

The domain is all values of

x

$x$ that make the expression defined.

Interval Notation:

(- 9, \infty)

$(- 9, \infty)$

Set-Builder Notation:

{x | x > - 9}

${x | x > - 9}$

Step 4

[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$